What is the molality of sucrose?
The molality of sucrose is: m = (0.1000 moles of sucrose)/(1.0000 kg of water) = 0.1000 moles/kG. A solution contains 0.1000 molal (m) sucrose (C12H22O11) in water. The molar mass of sucrose is 342.3 grams/mole.Click to see full answer. Correspondingly, what is the molarity of sucrose?A solution of sucrose (molar mass = 342.3 g/mole) in…
The molality of sucrose is: m = (0.1000 moles of sucrose)/(1.0000 kg of water) = 0.1000 moles/kG. A solution contains 0.1000 molal (m) sucrose (C12H22O11) in water. The molar mass of sucrose is 342.3 grams/mole.Click to see full answer. Correspondingly, what is the molarity of sucrose?A solution of sucrose (molar mass = 342.3 g/mole) in water has density 1.10 g/mL and molarity 1.00 M.Furthermore, how do you calculate the molality of a solution? Just multiply the number of grams, x, by 1 kilogram over 1,000 grams. Sometimes, we are given the number of grams of solute. Molality is the moles of solute per kilogram of solvent. To convert the number of grams of solute to moles of solute, we follow the equation: moles of solute = mass of solute / molar mass solute. Subsequently, question is, what is Molality example? Molality is defined as the number of moles of solute present in 1000 gm of the solvent. Unlike molarity, molality does not change with temperature since mass is affected by change in temperature. Example: Calculate the molality of a solution prepared from 29.22 grams of NaCl in 2.00 kg of water.How do you calculate the molality of NaCl?so moles NaCl = 70.128 g / (58.44 g/mol) = 1.2 mol . Plug moles value and the mass of the solvent into the molality formula. Divide 1.2 mol by 1.5 kg, and you’ll find out that the molality of the NaCl solution is 0.8 molal (in standard molality units: 0.8 mol/kg).
